c,#include,,void bubbleSort(int arr[], int n) {, int i, j, temp;, for (i = 0; i< n-1; i++) {, for (j = 0; j< n-i-1; j++) {, if (arr[j] > arr[j+1]) {, temp = arr[j];, arr[j] = arr[j+1];, arr[j+1] = temp;, }, }, },},,int main() {, int arr[] = {64, 34, 25, 12, 22, 11, 90};, int n = sizeof(arr)/sizeof(arr[0]);, bubbleSort(arr, n);, printf("Sorted array: \n");, for (int i=0; i< n; i++), printf("%d ", arr[i]);, return 0;,},
``groups
的表和一个名为 users
的表,并且它们通过 group_id
和 user_id
关联,可以使用如下的 SQL 查询:,,``sql,SELECT u.username FROM users u,JOIN groups g ON u.group_id = g.group_id,WHERE g.group_name = 'desired_group_name';,
``,,这条查询语句将返回属于指定用户组的所有用户的用户名。请根据实际的表名和字段名进行相应的调整。sql,ALTER USER 'root'@'localhost' IDENTIFIED BY '新密码';,
``,,请确保在执行此操作前已登录到MySQL服务器。Powered By Z-BlogPHP 1.7.3